Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

Can I simplify this for loop with a one-line code?

my_dict = {'a':'1', 'b':2, 'c':3}
my_list = ['a','b','d']
            
for element in my_list:
  if element not in my_dict:
     my_dict[element] =1

Can this for loop be replaced by a one-line code in Python? I can’t use dict or list comprehension to do it.

>Solution :

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

You can pass a dict into update():

my_dict = {'a':'1', 'b':2, 'c':3}
my_list = ['a','b','d']
            
my_dict.update({k:1 for k in my_list if k not in my_dict })

my_dict
# {'a': '1', 'b': 2, 'c': 3, 'd': 1}
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading