If you could just point me in the right direction I’m sure I could figure it out eventually.
I have a loop that works from i=1 to i=75. But I am able to run this a maximum of 3 times concurrently so all I could figure out is running it in 3 separate terminals as i=1 to i=25, i=26 to i=50, and i=51 to i=75.
Ideally I would want it run in the same script and for all 3 instances of the loop simultaneously and to begin at i=1 and end at i=75, however without overlapping i’s which have been completed or are being completed by a different instance of the loop.
Example processing:
- Loop1 begins i=1
- Loop2 skips i=1, Loop2 begins i=2
- Loop3 skips i=1,2, Loop3 begins i=3
- Loop2 completes i=2, Loop2 skips i=3, Loop2 begins i=4
- Loop3 completes i=3, Loop3 skips i=4, Loop3 begins i=5
- Loop1 completes i=1, Loop1 skips i=2,3,4,5 Loop1 begins i=6
- Loop1 completes i=6, Loop1 begins i=7
- Loop3 completes i=5, Loop3 skips i=7, Loop3 begins i=8
the structure of the loop is basically like this
u=0
while [ $u -lt 1000 ]
do
((u++))
i=$1
while [ $i -le $2 ]
do
curl #(that sends begining command $i)
sleep 60
variable1=$(curl $i) #command that outputs a number which can change every 60 seconds
variable2=$(curl $i) #command that outputs a number which is static
counter=0
until [ variable1 -ne $variable2 ]
do
((counter++))
echo waiting 60 seconds
echo times waited: $counter
sleep 60
variable1=$(curl $i) #command that outputs a number which can change every 60 seconds
variable2=$(curl $i) #command that outputs a number which is static
curl #(that sends ending command $i)
((i++))
done
done
>Solution :
I provide a simple way to accomplish this, and I let you to customize it per your needs:
#!/bin/bash
function myLoopFunction {
param1 = $1
param2 = $2
# Some code...
}
myLoopFunction value1a value2a & # Run 1
myLoopFunction value1b value2b & # Run 2
myLoopFunction value1c value2c & # Run 3
wait # Wait for termination...