Cannot print called float variables

Im new to C and coding in general so, sorry if this issue is super easy to solve but. I cannot print called float type variables into new functions. INT type variables i can print but float just does not want to print its value when called into a new function.

First i tried to change the floats to ints and that worked

int main(){
int integerrrr=6;
call(integerrrr);
}

void call(int integerrrr){
printf("%d", integerrrr);

}

This worked and it did indeed print 6.

BUT doing the same but with floats provides 0.00000:

int main(){
float integerrrr=6;
call(integerrrr);
}

void call(float integerrrr){
printf("%f", integerrrr);

}

How do i correctly call and then print float variables?

>Solution :

You could simply define call above main instead of below it. The compiler must have seen the declaration of functions when they are used, so a forward declaration like pm100 suggests is one way. Moving the whole definition above main is the another (that does not require a forward declaration).

#include <stdio.h>

void call(float integerrrr){
    printf("%f", integerrrr);
}

int main(void){
    float integerrrr = 6;
    call(integerrrr);        // now the compiler knows about this function
}

INT type variables i can print but float just does not

If your program actually compiles as-is it will use an old (obsolete) rule that makes an implicit declaration of undeclared functions when they are used. The implicit declaration would be int call(); – which does not match your actual function. The program (even the one that seems to be working) therefore had undefined behavior.