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cannot write function that checks in "X" has won the game in Tic Tac Toe (Python)

April 20, 2022

I am attending a course at EDx about AI in python. We were asked to build a program that played Tic Tac Toe.I have written this function that checks if "x" has won the game. The thing is my IDE pycharm finds an error:

An illegal target for a variable annotation

When I try to run the function I get this:

Traceback (most recent call last):
  File "/home/jason/miniconda3/envs/TicTacToe/lib/python3.9/code.py", line 90, in runcode
    exec(code, self.locals)
  File "<input>", line 1, in <module>
  File "/home/jason/.local/share/JetBrains/Toolbox/apps/PyCharm-P/ch-0/221.5080.212/plugins/python/helpers/pydev/_pydev_bundle/pydev_umd.py", line 198, in runfile
    pydev_imports.execfile(filename, global_vars, local_vars)  # execute the script
  File "/home/jason/.local/share/JetBrains/Toolbox/apps/PyCharm-P/ch-0/221.5080.212/plugins/python/helpers/pydev/_pydev_imps/_pydev_execfile.py", line 18, in execfile
    exec(compile(contents+"\n", file, 'exec'), glob, loc)
  File "/mnt/2ABA103F2BF5D2E6/PycharmProjects/TicTacToe/tictactoe.py", line 76
    for i in range(len(board):
                             ^
SyntaxError: invalid syntax

def winner(board):
"""
Returns the winner of the game, if there is one.
"""
if board[0][0] == X and board[1][1] == X and board[2][2] == X:
    return X

elif board[0][2] == X and board[1][1] == X and board[2][0] == X:
    return X
else:
    for i in range(len(board):
        if board[i][0] == X and board[i][1] == X and board[i][2] == X:
            return X

    for i in range(len(board)):
        if board[0][i] == X and board[1][i] == X and board[2][i] == X:
            return X

>Solution :

You miss the closing bracket. Try following the code.
for i in range(len(board)):

def winner(board):
"""
Returns the winner of the game, if there is one.
"""
if board[0][0] == X and board[1][1] == X and board[2][2] == X:
    return X

elif board[0][2] == X and board[1][1] == X and board[2][0] == X:
    return X
else:
    for i in range(len(board)):
        if board[i][0] == X and board[i][1] == X and board[i][2] == X:
            return X

    for i in range(len(board)):
        if board[0][i] == X and board[1][i] == X and board[2][i] == X:
            return X