I have a DB like this:
a <-c(4, 2, 10, 2, 10, 6, 2)
b <-c(4, 6, 70, 8, 18, 4, 3)
rbind(a,b)
I can create something like this:
x <- (4, 4, 2, 6, 10, 70, 2, 8, 10, 18, 6, 4, 3)
A DB that contains a and b order in this way, it is possible? I need to do a time series and the value must be in the same position
>Solution :
rbind works only when both the vectors are of the same length or else it will give unexpected output. i.e.
> rbind(c(4, 3, 5), c(3, 4))
[,1] [,2] [,3]
[1,] 4 3 5
[2,] 3 4 3
Warning message:
In rbind(c(4, 3, 5), c(3, 4)) :
number of columns of result is not a multiple of vector length (arg 2)
and when we do c to make a vector, it returns an extra 3 from recycling
A more general approach is to order based on the sequence of values in both vector while concatenating the vectors`
c(a, b)[order(c(seq_along(a), seq_along(b)))]
[1] 4 4 2 6 10 70 2 8 10 18 6 4 2 3