check And Count Value over php array

i am trying to count the number of times value is between 2 elements of array
first array is the company grade

Comps Esg Grades

$arr1 = [1,2,3,9,5,6,20,35,9,10];

the second array is the compere array

Final Compare

$arr2 = [0,2.2,10.4,20,30,44,60];

what i would like to achieve is
the number of times company is between to elements of array

first company grade is 1. so i am iterating over the arr2
like so to check if the value of 1 is between the elements
[0] and [1] [1] and [2] [2] and [3]
and so on

if the value is true so i add 1
when i am checking the next company value in this case its 2
so i need to add 1 to the previews check so the result should be 2
because i have 2 grade that in between 0 and 2.2

this is my code:

//Comps Esg Grades
$arr1 = [1,2,3,9,5,6,20,35,9,10];
//Final Compare
$arr2 = [0,1.7,10.4,20,30,44,60];
$countArray = [];

foreach ($arr1 as $r){
   
    foreach ($arr2 as $keyMain =>  $r2){
        $countArray[$keyMain] = 0;
       
    }
}

foreach ($arr1 as $r){
  
    foreach ($arr2 as $key =>  $r2){
        if($r2 > $r && $r2 < $arr2[$key + 1]){
            $currentVal = $countArray[$key];
            $countArray[$key] = $currentVal + 1;
         }
        
    }
}

and this is the result

   Array
   (
    [0] => 0
    [1] => 1
    [2] => 8
    [3] => 8
    [4] => 9
    [5] => 10
    [6] => 0
   )

>Solution :

I would run first on the ranges array ($arr2) and for each of those find how many items from the first array fit. The exact details though really depends on the expected result.

//Comps Esg Grades
$arr1 = [1,2,3,9,5,6,20,35,9,10];
//Final Compare
$arr2 = [0,1.7,10.4,20,30,44,60];
$countArray = [];


for ($i=0; $i<count($arr2)-1; $i++) {
    $min = $arr2[$i];
    $max = $arr2[$i+1];
    $countArray[$i] = 0;

    for ($j=0; $j<count($arr1); $j++) {
        
        if ($arr1[$j] >= $min && $arr1[$j] <= $max) {
            $countArray[$i]++;
        }
    }
}

print_r($countArray);

Output:

Array
(
    [0] => 1
    [1] => 7
    [2] => 1
    [3] => 1
    [4] => 1
    [5] => 0
)