Command not found error when i use shell command in a function

I am pretty new to shell script. I want to make a simple script that will install my script to the system. So I have tried to the write a simple script for that. Here is my code below.

#! /bin/bash
#Purpose: It is the install script for Template.sh
#Version:1.0
#Created Date: Thu Mar 16 04:10:20 PM IST 2023
#Modified Date:
#Author: Sayantan Sinharay
# START #

installPackage() {
  local PATH=$1
  if [[ -f PATH/template ]]; then
    cat template.sh >template
  else
    touch template
    cat template.sh >template
    chmod 777 template
    sudo mv template PATH
  fi
}
INSTALL_PATH="/bin/"

if [[ $# -eq 1 ]]; then
  INSTALL_PATH=$1
elif [[ $# -gt 1 ]]; then
  echo "ERROR: Expected 1 argument. Got $#"
  exit 1
fi

installPackage INSTALL_PATH
# touch hello.sh --> These are working
# chmod +x hello.sh --> These are working
# END #

On running this I am getting an command not found error

Here is the error in the terminal

./installTemplate.sh: line 15: touch: command not found
./installTemplate.sh: line 16: cat: command not found
./installTemplate.sh: line 17: chmod: command not found
./installTemplate.sh: line 18: sudo: command not found

>Solution :

installPackage INSTALL_PATH is likely a typo – you meant installPackage "$INSTALL_PATH".

The former passes the literal string INSTALL_PATH while the latter passes the contents of the variable.