Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

Compare dictionary keys (datetime) with list of tuples[1] and if matches return tuple[0]

I am a beginner(ish) with Python and having trouble with getting the correct syntax for this. Any help is greatly appreciated!

I have a dictionary and a list of tuples. I would like to compare the key of my dictionary to a value in the tuple, and if meets criteria return a different tuple value. Here’s the illustration:

dictionary = {datetime.datetime(2022, 4, 12, 9, 30): 30, datetime.datetime(2022, 4, 12, 11, 0): 60, datetime.datetime(2022, 4, 12, 13, 0): 30}

tuplelist = [(1, datetime.time(6, 45, 21)), (2, datetime.time(7, 15, 21)), (3, datetime.time(7, 45, 21)...etc)

The goal is to see which increment of 30 minutes my dictionary key falls into, and update it with the increment number stored in tuple list. What I tried:

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

for k,y in dictionary: 
  for i, t in tuplelist:
    if t <= k <= (t+ datetime.timedelta(minutes = 30)):
      dictionary[k] = t

The error I got is unable to unpack non iterable type datetime.

Any help and/or explanation is welcome! I am really enjoying learning to code but not from a CS background so always looking for the how it works in addition to just the correct syntax.

Thank you!

Update for working solution:

newdic = {}

for k,v in dictionary.items():
  for item in mylist:
    i, t = item
    if t <= k.time() <= (datetime.combine(datetime.today(),t) + datetime.timedelta(minutes=30)).time():
      newdic.update({i : v})
    else:
      continue

>Solution :

This is not the complete answer. See if it helps resolve early issues up to the comment.

import datetime

dictionary = {datetime.datetime(2022, 4, 12, 9, 30): 30,
              datetime.datetime(2022, 4, 12, 11, 0): 60,
              datetime.datetime(2022, 4, 12, 13, 0): 30}

tuplelist = [(1, datetime.time(6, 45, 21)), (2, datetime.time(7, 15, 21)),
             (3, datetime.time(7, 45, 21),)]
for k, y in dictionary.items():
    for item in tuplelist: # get each tuple from the list
        i, t = item # unpack the tuple into i and t
        print(f'{i=} {t=}') # Check i and t values
        # if t <= k <= (t + datetime.timedelta(minutes=30)):
        #     dictionary[k] = t
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading