Compare last 2 elements in an array

I want to compare elements in an array. The values of the array is getting from selecting the checkbox in a grid.I want to compare last 2 selected element’s data in the array. For example my array is like on first selection
let arr = [{aID:5, name: "trt", address:"tyuy", type:"ttype"}].
That time there is no need of comparison. On second checkbox selection

arr=[{aID:5, name: "trt", address:"tyuy", type:"ttype"},
{aID:6, name: "trt", address:"thyr", type:"ttype"},
]

compare 2 elements type and name be same, my code is like,

for (let i = 0; i < selected.length; i++) {
      for (let k = i + 1; k < selected.length; k++) {
          if ((selected[i].type === selected[k].type) &&(selected[i].name === selected[k].name)) {
            this.setState({ selectedRowKeys: e, selectedRecords: selected })
          }
          else{
            return message.warning("Select lien with same type and Name.")
          }
      }
      if(selected.length === 1){
      this.setState({ selectedRowKeys: e, selectedRecords: selected })
      }

This code works perfectly on 2 selection but the isssue is starts from 3rd selection on third selction we selct different type and name row it also given checked as I per my code. I want to compare last 2 elements like,

let arr =[{aID:5, name: "trt", address:"tyuy", type:"ttype"},
{aID:6, name: "trt", address:"thyr", type:"ttype"},
{aID:6, name: "gdg", address:"thyr", type:"ptype"},
] 

expected result is not show the selection of the checkbox of different type and name and also show the warning.

>Solution :

let arr=[{aID:5, name: "trt", address:"tyuy", type:"ttype"},
  {aID:6, name: "trt", address:"thyr", type:"ttype"},
  ]

  if(arr.length > 1){
    if(arr[arr.length-1].type === arr[arr.length-2].type && arr[arr.length-1].name === arr[arr.length-2].name){
        //code if true
    }else{

    }
  }