I have two objects.
const arrayOne = [
{
label: "Categories",
to: "/categories",
id: "product_type",
},
{
label: "Colors",
to: "/colors",
id: "color",
},
{
label: "Materials",
to: "/materials",
id: "material",
},
{
label: "Sizes",
to: "/sizes",
id: "sizes",
},
{
label: "Designers",
to: "/designers",
id: "designer_slug",
},
{
label: "Stores",
to: "/stores",
id: "retailer_slug",
},
];
const arrayTwo = [
{
id: "gender",
label: "Gender",
lazy_loaded: false,
},
{
id: "product_type",
label: "Category",
lazy_loaded: false,
},
{
id: "quick_filters",
label: "Quick filters",
lazy_loaded: false,
},
{
id: "final_price",
label: "Price",
lazy_loaded: false,
},
{
id: "color",
label: "Color",
lazy_loaded: false,
},
{
id: "material",
label: "Material",
lazy_loaded: false,
},
{
id: "designer_slug",
label: "Brand",
lazy_loaded: true,
},
{
id: "retailer_slug",
label: "Store",
lazy_loaded: true,
},
];
As you can see they both have the key ‘id’. If the IDs in arrayOne aren’t in arrayTwo, I would like them to be removed from arrayOne (the whole object). So in this case, only the object with "sizes" should be removed from arrayOne. How would I go about doing this? Thanks in advance!
>Solution :
you could utilize filter:
const newArrayOne = arrayOne.filter(x => arrayTwo.find(y => y.id === x.id))