I have a hard time doing the arithmetic statement
Convert the tuple, "Third" to an array.
Double all the elements in "Third"
Add the elements in this array to the elements in "Fourth".
To do this, use only 1 arithmetic statement. Store this result as "Fifth" and print it.
Hint Answer should look like this:
Fifth = 2*(_) + _____
print (Fifth)
third = (-6,-18,-10,-4,-90,-55,-56)
fourth =[6],[18],[10],[4],[90],[55],[56]
fourth = np.array(fourth)
print(third)
print(type(third))
print("After converting Python tuple to array")
arr = np.asarray(third)
print(arr)
print(type(arr))
fifth = 2*arr
print(fifth)
output:
(-6, -18, -10, -4, -90, -55, -56)
<class 'tuple'>
After converting Python tuple to array
[ -6 -18 -10 -4 -90 -55 -56]
<class 'numpy.ndarray'>
[ -12 -36 -20 -8 -180 -110 -112]
>Solution :
The numpy.ndarray type (docs) supports addition using the + operator. However, in your example my guess is that 2*arr + fourth will not produce the result you are looking for because fourth is of shape (7,1) while arr is of shape (7,), so arr + fourth would be of shape (7,7).
There are multiple ways to get fourth into shape (7,). fourth.flatten() will work (docs), as will numpy indexing, e.g. fourth[:,0].
Try this runnable example
import numpy as np
third = (-6,-18,-10,-4,-90,-55,-56)
fourth =[6],[18],[10],[4],[90],[55],[56]
fourth = np.array(fourth)
print(third)
print(type(third))
print("After converting Python tuple to array")
arr = np.asarray(third)
print(arr)
print(type(arr))
print(f"{arr.shape=}, {fourth.shape=}, {fourth.flatten().shape=}, {fourth[:,0].shape=}")
fifth = 2*arr + fourth[:,0]
print(fifth)<script src="https://modularizer.github.io/pyprez/pyprez.min.js"></script>p.s. when asking a question make sure to post your attempt as well as the traceback of the error produced