I have 7 python dictionaries each named after the format songn, for example song1, song2, etc. Each dictionary includes the following information about a song: name, duration, artist. I created a list of songs, called playlist full of the form [song1, song2, song3...,song7].
Here is my code:
song1 = {"name": "Wake Me Up", "duration": 3.5, "artist": "Wham"}
song2 = {"name": "I Want Your...", "duration": 4.3, "artist": "Wham"}
song3 = {"name": "Thriller", "duration": 3.8, "artist": "MJ"}
song4 = {"name": "Monster", "duration": 3.5, "artist": "Rhianna and Eminem"}
song5 = {"name": "Poison", "duration": 5.0, "artist": "Bel Biv Devoe"}
song6 = {"name": "Classic", "duration": 2.5, "artist": "MKTO"}
song7 = {"name": "Edge of Seventeen", "duration": 5.3, "artist": "Stevie Nicks"}
playlist_full = []
for i in range(1, 8):
song_i = "song"+str(i)
playlist_full.append(song_i)
Now I am trying to use an item in the playlist_full list to in turn get the name of the song in the corresponding dictionary. For example, to see the name of song3, I would like to run:
playlist_full[2].get("name")
The problem is that while playlist[2] is song3, python recognizes it only as a string, and I need python to realize that that string is also the name of a dictionary. What code will allow me to use that string name as the name of the corresponding dictionary?
>Solution :
You could use eval() like:
eval(playlist_full[2]).get("name")
which would do exactly what you want, evaluate the string as python code.
It’s not great practice though. It would be better/safer to store the songs themselves in a dictionary or list that can have non-eval’d references.