Count how many times can a number be divided by 2

n = int(input())
counter = 0
while n > 0:
   if (n // 2) > 1:
    counter = counter +1
    
print (counter)

Hi,
I am a python learner and I am having problems with this homework I was given.

Read a natural number from the input.
Find out how many times in a row this number can be divided by two
(e.g. 80 -> 40 -> 20 -> 10 -> 5, the answer is 4 times)

And I should use while loop to do it.

Any Ideas, because I really don’t have any idea how to do it.
This is my best try

>Solution :

Your while loop condition is wrong.
While the number is evenly divisible by 2, divide it by 2 and increment counter

num = int(input('Enter a number: '))

counter = 0
while num % 2 == 0:
    num = num / 2
    counter = counter + 1

print(counter)