Countdown the chances in loop for guessing game

i made 5 chances for the guesser to guess the random number. Everytime the guesser did wrong, i want to print

"Nice try, guess again (try bigger), you get {x} chance left."

the x is a countdown, so first wrong guess, will say, you get 4 chances left,
then another wrong got 3 chances left and so on. how to do that? how to add loop on the x.

so this is my unsuccessful code:

import random

secret_num = random.randint(1,20)


print('Guess the number from 1-20 (you get 5 chances)')
for guess_chance in range (1,6):
    guess = int(input("Input guess number: "))

    if guess < secret_num:
        x = 5
        x -= 1
        print(f'Nice try, guess again (try bigger), you get {x} chance left.')
    elif guess > secret_num:
        x = 5
        x -= 1
        print(f'Nice try, guess again (try smaller), you get {x} chance left.')

    else:
        break

if guess == secret_num:
    print('Congratz, you guess correctly in' + str(guess_chance) + 'times.')
else:
    print('Nope, the correct number is ' + str(secret_num) + '.')

>Solution :

You need to do x = 5 before for guess_chance in range...) and remove it from inside the loop.

print('Guess the number from 1-20 (you get 5 chances)')

x = 5

for guess_chance in range(1, 6):
    guess = int(input("Input guess number: "))

    if guess < secret_num:
        x -= 1
        print(f'Nice try, guess again (try bigger), you get {x} chance left.')

    elif guess > secret_num:
        x -= 1
        print(f'Nice try, guess again (try smaller), you get {x} chance left.')

    else:
        break

Otherwise, each guess you are resetting it to 5 tries and then subtracting one… which presumably always shows 4 tries…

There are many other ways to solve this… I just picked the one that changed your code the least

and when combined with your range this is a bit redundant

x = 6 - guess_chance would work

as would just iterating the range in reverse