Need to get nested lists from the list in python
list_values=[('BNB', '161221'),
('BNB', '171221'),
('BNB', '241221'),
('BNB', '280122'),
('BNB', '311221'),
('BTC', '161221'),
('BTC', '171221'),
('BTC', '241221'),
('BTC', '250222'),
('BTC', '250322'),
('BTC', '280122'),
('BTC', '311221')]
The output of lists needed is
List_op=[[('BNB', '161221'),
('BNB', '171221'),
('BNB', '241221'),
('BNB', '280122'),
('BNB', '311221')],
[('BTC', '161221'),
('BTC', '171221'),
('BTC', '241221'),
('BTC', '250222'),
('BTC', '250322'),
('BTC', '280122'),
('BTC', '311221')]]
I have tried with some list comprehension methods, but couldnt get this. Help is appreciated.
>Solution :
A simple solution:
from collections import defaultdict
list_values = [
('BNB', '161221'),
('BNB', '171221'),
('BNB', '241221'),
('BNB', '280122'),
('BNB', '311221'),
('BTC', '161221'),
('BTC', '171221'),
('BTC', '241221'),
('BTC', '250222'),
('BTC', '250322'),
('BTC', '280122'),
('BTC', '311221')
]
# a dict might be a better data type here
result = defaultdict(list)
for k, v in list_values:
result[k].append(v)
print(result)
# but if you need a list of lists instead of a dictionary:
result = defaultdict(list)
for k, v in list_values:
result[k].append((k, v))
list_op = [*result.values()]
print(list_op)
Output:
defaultdict(<class 'list'>, {'BNB': ['161221', '171221', '241221', '280122', '311221'], 'BTC': ['161221', '171221', '241221', '250222', '250322', '280122', '311221']})
[[('BNB', '161221'), ('BNB', '171221'), ('BNB', '241221'), ('BNB', '280122'), ('BNB', '311221')], [('BTC', '161221'), ('BTC', '171221'), ('BTC', '241221'), ('BTC', '250222'), ('BTC', '250322'), ('BTC', '280122'), ('BTC', '311221')]]