create tuple from ranges in python

February 28, 2023

Is there a way in python to create a tuple of months and years (as: [(2020, 1),(2020,2)...] ) by using the tuple() function?

My code:

monthyears = []
for y in range(2020,2017,-1):
    if y == 2018:
        m_end = 6
    else:
        m_end = 0
    for m in range(12,m_end,-1):
        monthyears.append((y,m))

output:

[(2020, 12),
 (2020, 11),
 (2020, 10),
 (2020, 9),
 (2020, 8),
 (2020, 7),
 (2020, 6),
 (2020, 5),
 (2020, 4),
 (2020, 3),
 (2020, 2),
 (2020, 1),
 (2019, 12),
 (2019, 11),
 (2019, 10),
 (2019, 9),
 (2019, 8),
 (2019, 7),
 (2019, 6),
 (2019, 5),
 (2019, 4),
 (2019, 3),
 (2019, 2),
 (2019, 1),
 (2018, 12),
 (2018, 11),
 (2018, 10),
 (2018, 9),
 (2018, 8),
 (2018, 7)]

for loops are fine, but I’d like to learn a new trick, if it exists.

>Solution :

Try this:

>>> tuple((y, m) for y in range(2020, 2017, -1) for m in range(12, (6 if y == 2018 else 0), -1))

# you can use 'in' if you want to check multi-year
# >>> tuple((y, m) for y in range(2020, 2017, -1) for m in range(12, (6 if y == 2018 else 0), -1))

((2020, 12),
 (2020, 11),
 (2020, 10),
 (2020, 9),
 (2020, 8),
 (2020, 7),
 (2020, 6),
 (2020, 5),
 (2020, 4),
 (2020, 3),
 (2020, 2),
 (2020, 1),
 (2019, 12),
 (2019, 11),
 (2019, 10),
 (2019, 9),
 (2019, 8),
 (2019, 7),
 (2019, 6),
 (2019, 5),
 (2019, 4),
 (2019, 3),
 (2019, 2),
 (2019, 1),
 (2018, 12),
 (2018, 11),
 (2018, 10),
 (2018, 9),
 (2018, 8),
 (2018, 7))