I have an array of objects with duplicates:
[
{
"code": "d1",
"title": "Title 1"
},
{
"code": "d2",
"title": "Title 2"
},
{
"code": "d3",
"title": "Title 3"
},
{
"code": "d4",
"title": "Title 4"
},
{
"code": "d4",
"title": "Title 4"
},
{
"code": "d3",
"title": "Title 3"
}
]So i want the output to be having only the once which doesn’t have duplicates included like below:
[
{
"code": "d1",
"title": "Title 1"
},
{
"code": "d2",
"title": "Title 2"
}
]Any help would be appreciated, Thanks!
>Solution :
Here is one way of doing it:
const products=[
{
"code": "d1",
"title": "Title 1"
},
{
"code": "d2",
"title": "Title 2"
},
{
"code": "d3",
"title": "Title 3"
},
{
"code": "d4",
"title": "Title 4"
},
{
"code": "d4",
"title": "Title 4"
},
{
"code": "d3",
"title": "Title 3"
}
];
const res=Object.entries(products.reduce((a,c)=>{
(a[c.code+"|"+c.title]??=[]).push(c);
return a;
},{})).reduce((a,[k,v])=>{
if(v.length==1) a.push(v[0]);
return a;
},[]);
console.log(res);My approach involves two .reduce() loops:
- In the first one I generate an object that collects all elements of the original array behind a compound key made up of the properties of the elements.
- the object is then converted into an array again with
Object.entries() - and in a second
.reduce()only those elements will be collected (i. e.: their first element) into the target array that have a length of1