Destructing string array optional parameters in TypeScript?

I need to implement a string concatenate function, the functionality shows below,

function concatenation(original: string, name1?, name2?){
  return original + name1 + name2;
}

However, the question is, there can be more parameters about name; therefore, this is a not a good coding style. I want to change its like shows below.

function concatenation(original: string, name?:[string]){
  return original + ...name1;
}

But in this way, the program will report an error. How could I achieve it?

>Solution :

You can use rest with join as:

function concatenation(original: string, name1?, name2?) {
  return original + name1 + name2;
}
concatenation('Original', 'Name1', 'Name2', 'Name3');

This can handle any number of string arguments

function concatenation2(...names: string[]) {
  return names.join('');
}

concatenation2('Original', 'Name1', 'Name2', 'Name3');

function concatenation2(...names) {
  return names.join('');
}

console.log(concatenation2('Original', 'Name1', 'Name2', 'Name3'));