I have an issue about display the value of a variable with double date type.
I already had looked at here, text, text and here. However it did not help me.
Below is the issue:
Here is the **code with scanf command. **
#include <stdio.h>
int main(){
double a, b, c , x0, Delta;
printf("Inter three numbers:");
scanf("%lf, %lf, %lf", &a, &b, &c);
Delta = b*b - 4*a*c;
printf("The value of Delta is %f \n", Delta);
x0 = -b/(2.0*a);
printf("\n the value of x0= %f", x0);
return 0;
}
With scanf command
I type 1 2 1, then $x0=0.000000$. It is the wrong result.
Without scanf command
If I type $a=1,b=2,c=1$ directly, then I got x0 = 1.000000.
I want to use scanf command and obtain the correct result. It mean to obtain x0=1.000000 when a=1, b =2, c=1.
>Solution :
Your scanf format string has commas between the numbers, so that’s how it’s expecting the input to look.
If you enter 1 2 1, the first %lf is matched by 1, but then 2 doesn’t match the comma, so it stops reading at that point, leaving b and c uninitialized.
You need to either enter the numbers with commas between them, or remove the commas from the format string.