Django href for html

How i can make link to this urls.py? I tried to pass the link through all the methods I know but they don’t work and gave an error

    path('category/<slug:gender_slug>/<slug:category_slug>/', views.StuffCategory.as_view(), name='category'),

html:

{% get_genders as genders %}
                    {% for gender in genders %}
                <li>
                    <!-- First Tier Drop Down -->
                    <label for="drop-2" class="toggle">Категории <span class="fa fa-angle-down"
                                                                       aria-hidden="true"></span> </label>

                    <a href="/">{{ gender }} <span class="fa fa-angle-down" aria-hidden="true"></span></a>
                    <input type="checkbox" id="drop-2">

                    <ul>
                        {% get_categories as categories %}
                        {% for category in categories %}
                        <li><a href="/">{{category.name}}</a></li>
                        {% endfor %}
                    </ul>
                </li>
                    {% endfor %}

views.py

class StuffCategory(ListView):
    model = Stuff
    template_name = 'shop/shop.html'
    context_object_name = 'stuffs'

    def get_queryset(self):
        queryset = Stuff.objects.filter(draft=False)
        if self.kwargs.get('category_slug'):
            queryset = queryset.filter(category__slug=self.kwargs['category_slug'])
        if self.kwargs.get('gender_slug'):
            queryset = queryset.filter(gender__slug=self.kwargs['gender_slug'])
        return queryset

>Solution :

Just pass the parameters that have been defined in url as below:

<a href="{% url 'category' gender_slug=gender category_slug=category %}">{{category.name}}</a>

For more information refer to official docs