If I define the destructor (or any autogenerated constructor) as default like this:
struct A {
~A() = default;
};
And then include this in several translation units, does this break the ODR? Can someone walk me through the steps at on the ODR page? Because i am struggling to understand if the compiler generated destructor will be inline or some other effect to prevent it from breaking the ODR.
>Solution :
No ODR violation. Member functions are implicitly inline if they are defined, defaulted or deleted inside a class definition.
https://en.cppreference.com/w/cpp/language/inline
The implicitly-generated member functions and any member function
declared as defaulted on its first declaration are inline just like
any other function defined inside a class definition.
// header file
// OK, implicit inline
struct A {
~A() {}
};
// header file
// OK, implicit inline
struct A {
~A() = default;
};
// header file
struct A {
~A();
};
// NOT ok, ODR violation when header is included in more than 1 TU
A::~A() {};
// header file
struct A {
~A();
};
// NOT ok, ODR violation when header is included in more than 1 TU
A::~A() = default;