Easy regex expression – taking the group up to the last comma

probably simple stuff but I don’t use regex that much.

Input: c1 = 7634, c2 = a,b, c3 = 8gd_, c4 = e,78

Desired Output:

c1 = 7634
c2 = a,b
c3 = 8gd_
c4 = e,78

Complexity (for me) – I don’t know how to define it so that for c2 it takes a,b with the comma. What I currently have:

(\w+)\s*=\s*((?:[^,].*?[^,])?)

trails the b.

Thanks upfront!

>Solution :

You can use

(\w+)\s*=\s*(.*?)(?=\s*,\s*\w+\s*=|$)

See the regex demo

Details:

• (\w+) – Group 1: one or more word chars
• \s*=\s* – a = sign enclosed with zero or more whitespaces
• (.*?) – Group 2: any zero or more chars other than line break chars as few as possible
• (?=\s*,\s*\w+\s*=|$) – immediately followed with a comma inside optional whitespaces + one or more word chars, zero or more whitespaces, and a = sign, or end of string.

Add \s* before $ if there can be trailing whitespaces.