Efficient way to separate an array of objects based on another array

For example I have an array of objects and an array as such:

const arrayObj = [
    {
        id: 1,
        name: "user1",
    },
    {
        id: 2,
        name: "user2",
    },
    {
        id: 3,
        name: "user3",
    },
]

const array = ["user1", "user2"]

How is it I’m able to separate arrayObj into two arrays based on array as such:

const array1 = [
    {
        id: 1,
        name: "user1",
    },
    {
        id: 2,
        name: "user2",
    },
]

const array2 = [
    {
        id: 3,
        name: "user3",
    },
]

I was thinking maybe something like this:

const filteredArray = arrayObj.filter((el) => {
  return array.some((f) => {
    return f === el.name;
  });
});

But is there a more efficient / quicker way?

>Solution :

Unless the arrays you’re dealing with are huge, your current code is fine.

If the arrays are huge and the current code is too slow, put the names into a Set and check Set.has instead of Array.some – Set.has is much faster when there are many elements in the Set.

const userSet = new Set(array);
const usersInUserSet = arrayObj.filter(user => userSet.has(user.name));