Error catching – incorrect number of arguments requested when calling the function

I get an interesting problem:

Let’s take such a function for example:

def SumNumbers(a,b,c,d,e,f):
  try:
    print("Marta: ",
        a,"+",b,'+',c,'+',d,'+',e,'+',f,
        '=',
        a + b + c + d + e + f)
  except TypeError:
      print("Enter the values for the 6 parameters of the program")

How we can handling this error in this case:

SumNumbers(1,2,3)

and in this case:

SumNumbers(1,2,3,4,5,5,6,77,7,8,88,8,8,8,8)

Of course, I mean handling this bug in the function body 🙂

My attempt to intercept a TypeError is unfortunately invalid 🙁

>Solution :

Use *args:

def SumNumbers(*args):
    if len(args) != 6:
      print("Enter the values for the 6 parameters of the program")
      return
    print(f"Marta: {' + '.join(str(i) for i in args)} = {sum(args)}")