Error returning an array from a consteval function

I’m trying to create a constant function that takes in a size int as a template parameter and returns an array that size with each index filled with its respective power of 2.

 template <int sz>
consteval int* conflagtab() {
    int ar[sz] = {};
    for (unsigned int i = 0; i < sz - 1; i++) {
        ar[i] = conflag(i);
    }
    return ar;
}

However when I am trying to use it I get the error:

call to consteval function "conflagtab<sz>() [with sz=31]" did not
produce a valid constant expression.

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

I tried putting it in global namespace to see if that had a change but it had no difference. I’m expecting it to just return a pointer to the array.

>Solution :

You can’t return a raw array from a consteval function, especially by pointer. Your example, if it were not consteval, would be a dangling pointer. Returning something that new[] created is not permitted in consteval

You can return a std::array:

template <int sz>
consteval std::array<int, sz> conflagtab() {
    std::array<int, sz> ar;
    for (unsigned int i = 0; i < sz - 1; i++) {
        ar[i] = conflag(i);
    }
    return ar;
}