error "Statement expected, found Py:RPAR" in the code

4 problems: ‘,’ or ‘)’ expected
Statement expected, found Py:COLON
End of statement expected
Statement expected, found Py:RPAR

def my_substr(string, num):
#    index = len(string) - 1
    return string(1: num)`

error in the 3 line

>Solution :

It looks like you’re trying to slice string. If that’s the case, that syntax uses square brackets ([]), not parentheses (()):

return string[1:num]
# Here ------^-----^