Evaluating a lambda function with if else f'y{x}' inside the sorted method

I have the following sorting problem:

Given a list of strings, return the list of strings
sorted, but group all strings starting with ‘x’ first.

Example: [‘mix’, ‘banana’ ,’xyz’, ‘apple’, ‘xanadu’, ‘aardvark’]
Will return: [‘xanadu’, ‘xyz’, ‘aardvark’, ‘apple’, ‘banana’ ,’mix’]

I solved by splitting the list into 2:

def front_x(words):

    return [w for w in words if w[0] == "x"] + [w for w in words if w[0] != "x"]

Another pythonic solution for this problem would be using sorted method, like this:

def front_x(words):

    return sorted(words, key=lambda x: x if x[0] == 'x' else f'y{x}')

I am having a hard time to understand what is going on after else. Any good soul to help me out? I’m grateful.

>Solution :

return sorted(words, key=lambda x: x if x[0] == 'x' else f'y{x}')

Translation:

"Return a sorted version of words. For each item x in words, use x for comparison when sorting, but only if x[0] is equal to the character 'x'. Otherwise, append 'y' to the front of x and use that for comparison instead"

The f'y{x}' syntax is the f-string syntax. It’s equivalent to:

"y" + str(x)

There are plenty of other equivalent ways to insert a character into a string. That’s just how it’s being done here.

So, if your word list was:

aardvark
xylophone
xamarin
xenophobia
zipper
apple
bagel
yams

The list would be sorted as if it contained the following:

yaardvark
xylophone
xamarin
xenophobia
yzipper
yapple
ybagel
yyams

And therefore the output would be:

xamarin
xenophobia
xylophone
aardvark
apple
bagel
yams
zipper

So, what is happening is that, when the list is sorted, items that start with 'x' will always appear before any other items.