Evaluating if (function<void()> == functor)?

How can i evaluate given expression (function<void()> == functor).

Kode example:

#include <vector>
#include <functional>
#include <iostream>
using namespace std;

void Foo() {
    cout << "Hi" << endl;
}

int main() {

    auto f = Foo;

    vector<function<void()>> vec;
    vector<function<void()>>::iterator it;

    vec.emplace_back(Foo);

    for (it = vec.begin(); it < vec.end(); it++) {
        // how to evaluate if (it == f)?

        //if (*it == f) { // Error
        //  
        //}
    }
}

Variabels values and points values in the above example:

>Solution :

std::function::target() will retrieve a pointer to the stored callable object. And that’s what you’re trying to compare.

You must specify the expected stored type, and target() will return nullptr if the type does not match.

(This means that if std::function holds a function pointer, target() will return a pointer-to-a-function-pointer.)

    if (*it->target<decltype(f)>() == f) { // Success

See it work in Compiler Explorer