I am doing some practice on find command but I don’t get the expected result when I attempt to use -execoption of it. The command I wrote just works without -exec option as the following:
$ find ~ \( -type f -not -perm 0600 \) -or \( -type d -name 'D*' \)
/home/baki/.bashrc
/home/baki/.bash_logout
/home/baki/.cache/motd.legal-displayed
/home/baki/.config/wslu/baseexec
/home/baki/.config/wslu/oemcp
/home/baki/.gitconfig
/home/baki/.landscape/sysinfo.log
/home/baki/.motd_shown
/home/baki/.profile
/home/baki/.ssh/known_hosts
/home/baki/.sudo_as_admin_successful
/home/baki/ssh_start
/home/baki/token
However, when I add the -exec option to the end of the command, it doesn’t give any output:
find ~ \( -type f -not -perm 0600 \) -or \( -type d -name 'D*' \) -exec ls -l '{}' ';'
I have searched about it but I couldn’t find a piece of useful information that can solve my problem.
Is my command wrong or is it about something else?
Thank you for your help.
>Solution :
The default -and operation has higher precedence than -or. Use extra parentheses:
find ~ \( \( -type f -not -perm 0600 \) -or \( -type d -name 'D*' \) \) -exec ls -l '{}' ';'
You can probably omit the inner parentheses in this case.