Extract a string after a number of forward slashes from inside a string

Hy have a string which corresponds to a file location in linux, i want to extract just the part of it that corresponds to the username and that always comes after the 6th forward slash and then store it in a new string variable:

str1 = "/usr/share/nginx/website/orders/jim/17jkyu.xlsx"
n = 0
user = ','

for ch in str1:
    if ch == '/':
        n += 1
    if n == 6:
        user.join(ch)
    if n == 7:
        break

print(user + '\n')

In this case i want to extract jim and put it into the string user.
So far is not working

>Solution :

Split the string then pull the index value.

str1 = "/usr/share/nginx/website/orders/jim/17jkyu.xlsx"
user = str1.split('/')[6]