Extract a substring from a string in Python – regex

August 1, 2024

Let’s say I have a long string with address data in format:

string = ... 'Something 3; Place: Something; City: NewYork; Street: Broadway; House: 7; Lat g: 33,105438; Long g: 12,749558; Object: Something;'...

I want to extract substring from that string starting from Place: to Long g: 12,749558. usinge regex findall().
Can anyone help me? Thanks!

I want to get from my string:

Place: Something; City: NewYork; Street: Broadway; House: 7; Lat g: 33,105438; Long g: 12,749558;

>Solution :

You can use the following regex pattern: r'Place:.*?Long g: \d+,\d+;'.

Code example:

import re

string = '... Something 3;  Place: Something; City: NewYork; Street: Broadway; House: 7; Lat g:  33,105438; Long g: 12,749558; Object: Something;...'
pattern = r'Place:.*?Long g: \d+,\d+;'
result = re.findall(pattern, string) # "Place: Something; City: NewYork; Street: Broadway; House: 7; Lat g:  33,105438; Long g: 12,749558;"