extract nth number in a string using bash commands

running the following command I get 0271, is there a way to get 0, 27, and 1 separately?

echo '!    ibrav = 0, nat = 27, ntyp = 1' | sed -r 's/[^1-9]*//g'

>Solution :

Use grep instead of sed. The -o option prints just the matching parts, and each match is on a separate line.

echo '!    ibrav = 0, nat = 27, ntyp = 1' | grep -E -o '[0-9]+'

Output:

0
27
1