Filter an array with another array with matching characters in javascript

June 27, 2022

Is it possible to have an array filter another array from matching each character?

I have a set of logs and a filter that look like this:

logs = [{id:1, log: "log1"}], {id:2, log: "log2"}, {id:3, log: "fail"}

filter = ["log"]

it should return

[{id:1, log: "log1"}, {id:2, log: "log2"}]

If my filter were to be

filter = ["1", "fai"]

the output would be

[{id:1, log: "log1"}, {id:3, log: "fail"]

>Solution :

You can use the function Array.prototype.filter along with the function Array.prototype.some in order to filter out the objects that don’t match the filter.

const match = (filter, key, array) => array.filter(o => filter.some(c => o[key].includes(c))),
      array = [{id:1, log: "log1"}, {id:2, log: "log2"}, {id:3, log: "fail"}];

console.log(match(["log"], "log", array));
console.log(match(["1", "fai"], "log", array));