Filter Python 2D Array based on 2nd Element

I have a python 2D array like this:

array = [('aaa', 20), ('bbb', 30), ('ccc', 40), ('ddd', 50)]

I want to filter this array based on the 2nd value in each set.
for example I want to keep only the items having the 2nd item >= 40

Expected output:

filtered_array =  [('ccc', 40), ('ddd', 50)]

I can achieve this with loops but is there an elegant way of filtering this?

>Solution :

Clearest:

[x for x in xs if x[1] >= 40]

Less clear:

list(filter(lambda x: x[1] >= 40, xs))

No loops at the Python level:

def f(xs):
    try:
        x = next(xs)
    except StopIteration:
        return
    if x[1] >= 40:
        yield x
    yield from f(xs)

list(f(iter(xs)))