I obtain today’s date by using:
> today <- format(Sys.time(), "%Y-%m-%d")
> # or use `today <- format(Sys.Date())`
> today
[1] "2021-12-23"
I hope to find a date specific days/months (let’s use 60 days or 2 months as example) ago, how could I do that in R?
The equivalent code in Python would be:
import datetime
from dateutil.relativedelta import relativedelta
day1 = datetime.date.today() - datetime.timedelta(days=60)
day2 = datetime.date.today() - relativedelta(months=2)
print(day1)
2021-10-24
print(day2)
2021-10-23
Sincere thanks for your help at advance.
>Solution :
If you are using lubridate you can simply add subtract days/months etc. like this.
library(lubridate)
today <- format(Sys.time(), "%Y-%m-%d")
today
ymd(today) - days(60)
ymd(today) - months(2)
> today
[1] "2021-12-23"
>
> ymd(today) - days(60)
[1] "2021-10-24"
>
> ymd(today) - months(2)
[1] "2021-10-23"