Find all index based on condition

December 12, 2021

How can I get all the index based on a condition for array of objects.
I have tried below code, but it’s returning only the first occurrence.

a = [
  {prop1:"abc",prop2:"yutu"},
  {prop1:"bnmb",prop2:"yutu"},
  {prop1:"zxvz",prop2:"qwrq"}];
    
index = a.findIndex(x => x.prop2 ==="yutu");

console.log(index);

>Solution :

The findIndex method returns the index of the first element in the
array that satisfies the provided testing function. Otherwise, it
returns -1, indicating that no element passed the test. – MDN

You can use reduce here:

const a = [
  { prop1: "abc", prop2: "yutu" },
  { prop1: "bnmb", prop2: "yutu" },
  { prop1: "zxvz", prop2: "qwrq" },
];

const result = a.reduce((acc, curr, i) => {
  if (curr.prop2 === "yutu") acc.push(i);
  return acc;
}, []);

console.log(result);