Find different elements when comparing two Python lists

I have two lists. X list is bigger, Y list is smaller.
I want to find elements from Y list that are different from elements in X list, but also elements that are not part of the any element in X list. Also, elements from X list can not be part of elements in Y list.

For example A A is part of A A B, AA B is part of AA BB but A C A, C BB, S are not part of any element in Y.

Also, you will see that X has C A and Y has CC A, that is not allowed.

X = ["A A B", "A B C", "AA BB", "BB C A", "A C B", "BB C A", "X", "C A"]
Y = ["A A", "A C A", "AA B", "C BB", "S", "CC A"]

I have tried something like this, with different place of else but it does not work good

for x in X:
    for y in Y:
        if x in y or y in x:
            continue
    else:
        print(y)

Requested result:

C BB
S

>Solution :

• Go over each element in Y.
• For each one, go over each element in X.
• If any of them contain each other in any direction – break.
• Else, take the item:

X = ["A A B", "A B C", "AA BB", "BB C A", "A C B", "BB C A", "X", "C A"]
Y = ["A A", "A C A", "AA B", "C BB", "S", "CC A"]

for y in Y:
    for x in X:
        if y in x or x in y:
            break
    else:
        print(y)

Gives:

C BB
S

This uses the for/else construct which means that the else part will only be executed if the loop executed to exhaustion, without breaking.

Or, the shorter way by using any:

for y in Y:
    if not any(y in x or x in y for x in X):
        print(y)

or, by De Morgan’s laws we can use all:

for y in Y:
    if all(y not in x and x not in y for x in X):
        print(y)