Find item in list of dicts

I have a list of dictionary something like this:

list = [
   {
      "ENT_AUT":[
         "2018-11-27"
      ]
   },
   {
      "ENT_NAT_REF_COD":"C87193"
   },
   {
      "ENT_NAM":"MONEYBASE LIMITED"
   },
   {
      "ENT_NAM_COM":"MONEYBASE LIMITED"
   },
   {
      "ENT_ADD":"Ewropa Business Centre, Triq Dun Karm"
   },
   {
      "ENT_TOW_CIT_RES":"Birkirkara"
   },
   {
      "ENT_POS_COD":"BKR 9034"
   },
   {
      "ENT_COU_RES":"MT"
   }
]

Here every dictionary will always contain only one key value pair. Now I need to know the value of ENT_NAM, ENT_AUT and etc all fields.

I tried something like this:

ENT_NAM = (list[2].values())[0]
print('ENT_NAM = ', ENT_NAM)

It works perfectly for this list but my problem is that the ‘ENT_NAM’ containing dictionary will not always be on the 2nd index of the list. How can I generalize this solution so that even if the order of the dictionary under the list changes, I always find a perfect solution?

>Solution :

If all of the keys are unique, you can flatten the list of dictionaries into a dictionary with a straightforward dictionary comprehension.

Note: you don’t want to use list as a name for a variable, as it is an important built-in type. Use something like lst instead.

{ k: v for d in lst for k, v in d.items() }

Result:

{'ENT_AUT': ['2018-11-27'], 'ENT_NAT_REF_COD': 'C87193', 
 'ENT_NAM': 'MONEYBASE LIMITED', 'ENT_NAM_COM': 'MONEYBASE LIMITED', 
 'ENT_ADD': 'Ewropa Business Centre, Triq Dun Karm', 
 'ENT_TOW_CIT_RES': 'Birkirkara', 'ENT_POS_COD': 'BKR 9034', 
 'ENT_COU_RES': 'MT'}

Getting the value for key 'ENT_NAM' is now just:

{ k: v for d in lst for k, v in d.items() }['ENT_NAM']