For loop in Python with indices

I’m making the transition from java to python and I’m confused about how for loops work in python. I know basically all for loops in python are for-each loops, but that’s not what I need. I’ve built a scraper, and I’m just trying to condense the code a little. My current issue is that I call for status codes in my responses, so I have ten or twelve lines of response1.status_code response2.status_code etc. If I were in java, I could write something along the lines of

for (int i=1; i<=12; i++){
    if (response[i].status_code != 200) 
        System.out.print("error in response"+[i])};

but that doesn’t seem to exist in python, so I’m not quite sure where to turn. Any advice is appreciated!

>Solution :

You can use this, if you already have the list / array but don’t know the size yet.

for idx,data in enumerate(content_list):
    print(idx) # will print the index of the loop starting from 0
    print(data) # will print the actual data,
    print(content_list[idx]) # will manually access the list using the index. both this and data will print the same thing

If you want to do a for loop with a set range, do this,

for i in range(1,12+1): #need to do plus 1 because python is upper bound exclusive
    print(i)

or a while loop like this.

i = 1
while i <= 12: #loop will end when i becomes 12.
    print(i)
    i += 1 #increments by 1

If each item is a separate variable and not a list, try this,

for i in range(1,12+1): 
    if eval(f'response{i}.status_code != 200'): #this is an eval function with an f string, the curly braces will dynamically assign the variable on each loop
        print("error in response" + str(i)) #you cant concat a string and int together unless you convert the int to a string like this.