Get a list of keys that match each item of another given list…?

my_dict = {
    'NONE': ['N', 'NE'],
    'VERY SLIGHT': ['VSLT', 'VT'],
    'SLIGHT': ['SLT', 'ST'],
    'FAINT': ['F', 'FT'],
    'MEDIUM': ['M', 'MM'],
    'STRONG': ['S', 'SG'],
    'VERY STRONG': ['VS', 'VG']
}

search_list = ['N', 'SLT', 'MM']

result_list = []

I want to search each item of search_list in values of my_dict and return the matching keys as list.

I need… result_list = [‘NONE’, ‘SLIGHT’, ‘MEDIUM’]

I got it by…

for i in search_list:
    for k, v in my_dict.items():
        if i in v:
            result_list.append(k)

how to get it in more simpler and quickest way to do it?

>Solution :

Nested comprehension is one option.

[k for k, v in my_dict.items() for x in search_list if x in v]