get all the naturals less than a number in ascending order

I’m making a quiz app, and the options are storage this way:

option1 = 'First option'
option2 = 'Second option'
option3 = 'Third option'
numberOfOptions = 3

As some questions will have 4 alternatives, others 2, I’m trying to create a method to dynamically retrieve the number of alternatives available.
For that, I have the numberOfOptions variable. Based on this number, I need to get all the natural numbers less than it until 1 (as in the example, [1, 2, 3]), where I need to add to 'option'. The final result must be:

['option1', 'option2', 'option3'];

For now, what I did was:

void options() {
  int numberOfOptions = 3;
   for (int i = 0; i < numberOfOptions; i++) {
   print('option${i + 1}');

 }
}

On the output I get option1, option2, option3, but I’m stuck trying to return it as a List

>Solution :

One elegant solution would be to make use of the List.generate() constructor and achieve our objective with just one line:

List<String>.generate(numberOfOptions, (int index) => 'option${index + 1}');

The List.generate() constructor takes two arguments:

• length;
• a generator function that has an index variable;

You can read more about it on the official documentation.

It can be useful as it’s much easier to read and leaner than a for-loop.