Is it possible, and how should regex look like to get everything after the closing bracket or get everything if there are no brackets at all?
example:
possible input 1:
[12,45] some text
possible input 2:
some text
expected to get:
some text
I found something like lookbehing conditional, and tried:
(?(?<=\])((?<=\])(.*))|(.*))
but didn’t work.
This works for the input with brackets:
(?<=\])(.*)
And this works for input without brackets:
(.*)
but is it possible to get one expression to match both input cases?
>Solution :
This regex, you need OR aka |:
(?<=]\s|^)[\w\s]+
# ^
# |
# there
The regular expression matches as follows:
| Node | Explanation |
|---|---|
(?<= |
look behind to see if there is: |
] |
] |
\s |
whitespace (\n, \r, \t, \f, and " ") |
| |
OR |
^ |
the beginning of the string |
) |
end of look-behind |
[\w\s]+ |
any character of: word characters (a-z, A- Z, 0-9, _), whitespace (\n, \r, \t, \f, and " ") (1 or more times (matching the most amount possible)) |