After trying to reverse a very simple math formula for the past day, I’ve given up after bumping my head against scipy.special.lambertw — which might not even be the correct place to be looking.
I have the following equation:
import numpy
# The following == 70.03
np.sqrt(np.log(742) * 742)
I’m trying to invert that equation — where inputing 70.03 would equal 742.
Here was my current attempt after playing around with an algebra solver and Wolfram Alpha:
from scipy.special import lambertw
np.power(np.power(np.e, lambertw(70.03)), 2)
This obviously produces an incorrect answer — but since algebra was so long ago, I’m basically lost as to how to produce a function that coverts 70.03 back into 742.
Thanks for any help!
>Solution :
From WolframAlpha I get
from scipy.special import lambertw
f = lambda x: x ** 2 / lambertw(x ** 2)
as the inverse.
indeed
f(70.03) gives (742.008379366021+0j)
but i dont have the mathematics to find what wolframalpha found, i hope you understand why f above is the inverse really