How can i changes the values in a nested list to those specified in a dict?

I have this code in which I have a list of lists and inside the sub-lists we got numbers. However, I also have a dict storing key-value pairs of name-number, in which the number is the index of the name stored in another list, but I want to replace all the numbers in the nested list with their respective names. Instead of having [1,9,13] I want to have [‘The Beach Chimney’, ‘Parlay’, ‘The Private Exhibit’].

out = [(ind,ind2) for ind,i in enumerate(rows) 
                  for ind2,y in enumerate(i) if y == '1']

list_of_restaurants_index = []
for empty_list in range(100):
  empty_list = []
  list_of_restaurants_index.append(empty_list)

for i in out:
  for empty_list in list_of_restaurants_index:
    if i[0] == list_of_restaurants_index.index(empty_list):
      empty_list.append(i[1])
print(list_of_restaurants_index)

restaurants_dict = {}
for i in header:
  restaurants_dict[i] = header.index(i)

Output:

[[1, 9, 13], [8, 14, 17], [6, 14], [4, 8, 9, 12], [1, 2, 5, 6, 12, 13, 18], [1, 4, 5, 8, 10, 11, 12], [1, 12, 14, 16], [3, 4, 5, 13, 14, 17, 18], [4, 9, 10, 12, 13, 14, 15, 18], [3, 16], [1, 3, 5, 10, 13], [1, 5, 10, 15, 17], [2, 4, 6, 7, 10, 13], [2, 4, 9, 12], [9, 11, 12, 13], [1, 3, 4, 7, 9, 17], [6, 8, 9, 10, 11, 13, 14, 15, 18], [2, 4, 6, 7, 8, 13], [4, 7, 10, 11, 13, 14, 16, 18], [7, 12, 16, 17, 18], [3, 7, 10, 13, 14], [1, 2, 3, 5, 8, 12, 14, 17, 18], [8, 10, 12, 13, 16, 17], [4, 5, 6, 7, 8, 11, 17], [1, 4, 7, 9, 13, 16], [4, 10, 12, 14, 15], [2, 3, 4, 11, 13, 14, 15, 17], [1, 2, 7, 8, 9, 16], [5, 6, 7], [4, 5, 6], [10, 16, 18], [6, 13, 14, 17], [1, 6, 16, 17], [1, 2, 4, 5, 10, 12, 15, 18], [3, 4, 10, 12, 14, 16, 18], [1, 2, 6, 8, 9, 11, 13, 14, 16, 17], [5, 6, 7], [1, 2, 5, 10, 13, 18], [4, 5, 13, 18], [5, 7, 9, 10, 11, 12, 15, 17], [2, 14], [4, 5, 9, 11, 12, 14], [1, 3, 5, 10, 11, 15], [3, 12, 13, 16], [1, 4, 5, 6, 7, 9, 11, 13, 14, 15], [4, 6, 9, 13, 15, 16, 18], [2, 3, 4, 6, 9, 12, 14, 15], [1, 7, 12, 14, 17], [5, 6, 8, 10, 11, 12, 15, 18], [2], [2], [4, 5, 7, 11, 12, 14], [1, 4, 9, 14, 18], [3, 6, 8, 15, 18], [1, 4, 7, 8, 14], [3, 4, 7, 11, 15], [1, 4, 5, 6, 10, 13, 14, 15, 16, 18], [2], [2], [5, 6, 8, 14, 15, 16, 18], [6], [8, 10, 12, 16], [1, 4, 5, 10, 14, 17, 18], [6], [5, 6, 9, 10, 13, 14], [1, 11, 12, 17], [1, 5, 10, 14, 15], [3, 4, 6, 9, 10, 15, 18], [4, 8, 10, 16, 17, 18], [4, 7, 14, 17], [1, 2, 3, 9, 16], [10, 12, 14, 16], [1, 2, 8, 10, 15], [1, 2, 4, 10, 13, 17], [3, 7, 17], [4, 5, 6], [4, 6, 11, 12, 17], [1, 2, 7, 8, 13, 16], [1, 2, 4, 8, 13], [8, 11], [1, 4, 5, 6, 7, 18], [1, 4, 5, 11, 12, 14, 17], [5, 8, 9, 14], [2], [4, 5, 7, 10, 14, 16], [6], [1, 2, 3, 4, 7, 11, 13, 14], [7, 12, 14], [3, 4, 7, 11, 13], [1, 2, 3, 4, 6, 7, 8, 9, 14, 15], [2], [6], [5, 12, 15, 16, 17, 18], [3, 4, 5, 11, 12, 13], [3, 5, 6, 14, 17, 18], [9, 12, 13, 15], [4, 14, 15, 16, 18], [4, 8], [3], [3]]

Also, here’s what the dict is storing:

{'': 0, 'The Beach Chimney': 1, "The Pirate's Harvest": 2, 'The Square Dragon': 3, 'The Spicy Trumpet': 4, 'Vertigo': 5, 'Drifters': 6, 'The Tulip': 7, 'Seawise': 8, 'Parlay': 9, 'The Modern Salmon': 10, 'The Bitter Windmill': 11, 'The Minty Window': 12, 'The Private Exhibit': 13, 'Enigma': 14, 'The Lighthouse': 15, 'Harlequin': 16, 'Midnight': 17, 'Gastrognome': 18}

obs: header is a list containing the names.

>Solution :

Not sure the purpose of the dict.

empty_list.append(i[1]) seems to be appending a number

That number happens to align with the indicies of the strings you want.

Therefore, you could instead use

name = header[i[1]]
empty_list.append(name)