how can I count every item in a list by a specific range? Also, why the last item in my output is not sorted?

I have written a code to receive the user input as a list.

def lst_data():
    lst = []
    total = int(input('Number of Data: '))
    for number in range(0, total):
        user_data = int(input('Enter the Data: '))
        lst.sort()
        lst.append(user_data)
    print(lst)

the output is:

[50, 51, 52, 53, 54, 55, 57, 58, 59, 60, 61, 62, 63, 64, 65, 68, 70, 70, 71, 72, 73, 74, 75, 76, 77, 79, 79, 80, 80, 81, 82, 84, 86, 87, 88, 89, 89, 90, 91, 83]

The next step I want to do is count every item on that list by every 6 numbers like 50-55 = ???, 56-61 = ???, 62-67 =???, and so on.

I’ve been trying with:

counter =  0
for i in last:
    if 50 < i < 55:
    counter += 1

print(counter)

it works but I have to repeat the code over and over and value in the "if statement" has to be from the user input

how can i figure this out? and I want to check if there is any way to make my code simpler

>Solution :

I think this is what you’re trying to do:

def count(lo, hi, _list):
    return sum(lo <= e <= hi for e in _list)

nd = int(input('Number of data items: '))
data = []

for _ in range(nd):
    datum = int(input('Enter datum: '))
    data.append(datum)

lo = int(input('Enter low range value: '))
hi = int(input('Enter high range value: '))

print(f'There are {count(lo, hi, data)} items in the range {lo}-{hi}')

Example:

Number of data items: 5
Enter datum: 2
Enter datum: 1
Enter datum: 3
Enter datum: 5
Enter datum: 6
Enter low range value: 1
Enter high range value: 5
There are 4 items in the range 1-5

Note:

There is no reason to sort the list