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How can I let the output return True or False based on the input of the list?

December 8, 2021

So I have a list hand whose data is something like this ['AS', 'AD', 'AC', 'CH', 'CS']. Now I have to find the first character of each element in the list and see if there are 3 identical letters and 2 identical letters or not.

Note: they must all be in order though.. like always x,x,x,y,y or y,y,x,x,x. Any other combination, like x,y,y,x,x or x,y,x,y,x, will return False

So for example

['AS', 'AD', 'AC', 'CH', 'CS'] returns True because there are 3 A and 2 C.

['AS', 'SD', 'SC', 'CH', 'CS'] returns False because the order is not right

['CS', 'CD', 'AC', 'AH', 'AS'] returns True because there are 3 A and 2 C

['AS', 'CD', 'DC', 'AH', 'CS'] returns False because none of the characters appear 3 times and 2 times.

Here is my code so far, which doesn’t work…

hand = ['AS', 'AD', 'AC', 'CH', 'CS']
updated_hands = list([x[1] for x in hand])
if ((updated_hands[0] == updated_hands[1] == updated_hands[2]) or (updated_hands[2] == updated_hands[3] == updated_hands[4])) and ((updated_hands[3] == updated_hands[4]) or (updated_hands[0] == updated_hands[1])):
    print('True')
else:
    print('False')

What changes should I make to this?

>Solution :

Here is something that should work for arbitrary lengths and orders:

hands = [['AS', 'AD', 'AC', 'CH', 'CS']]
hands.append(['AS', 'SD', 'SC', 'CH', 'CS'])
hands.append(['CS', 'CD', 'AC', 'AH', 'AS'])
hands.append(['AS', 'CD', 'DC', 'AH', 'CS'])

for hand in hands:

    condition = True

    last_count = 1
    last_item = hand.pop(0)[0]

    while hand:
        item = hand.pop(0)

        if (item[0] == last_item):
            last_count += 1 

        if (last_item != item[0]):
            if (last_count == 2) or (last_count == 3):
                condition = True
            else:
                condition = False
                break

        last_item = item[0]

    print(condition)

Outputs: