How can I make a for statement work when comparing two apended lists?

The last for statement does not work. I am comparing the outputs of two functions (which are each being appended as a list). Essentially, if the output of the first item in the list for function A is larger than the first item in the list for function B then I would like to print a 1, if it is less then I would like to print 0, otherwise 0.5. However, when I run the code I get 1 for each value compares across both lists. This is false because I’ve manually checked each value (there should be 1s and 0s and no 0.5s).

from IPython.lib.display import IFrame
#Exptected Value

import numpy as np
import math
natural_log = np.log(1)


Outcomes = [[20, 0],[ 20, 0],[ 20, 0],[ 20, 0],[ 20, 0]]

Probabilities = [[0.001, 0.999],[  0.01, 0.99],[  0.1, 0.9],[  0.25, 0.75],[  0.5, 0.5]]


Y = []
PT= []

for i in range(0,len(Outcomes)):
    Y.append(Outcomes[i][0]*Probabilities[i][0] + Outcomes[i][1]*Probabilities[i][1])
    
for i in range(0,len(Outcomes)):
    PT.append((math.exp(-(-np.log(Probabilities[i][0]))**0.5))*(Outcomes[i][0]**0.5)+(math.exp(-(-np.log(Probabilities[i][1]))**0.5))*(Outcomes[i][1]**0.5))

for i in range(0,len(Outcomes)):
        if PT > Y:
            print("gamble",i+1,"PT output = 1")
        if PT < Y:
            print("gamble",i+1,"PT output = 0")
        if PT ==Y:
            print("gamble",i+1,"PT output = 0.5")

print(PT)
print(Y)

>Solution :

try to modify following code to your requirement.

a=[1,2,3,4]
b=[1,3,2,1]

for i,j in zip(a,b):
    if i==j:
        print("it's a match.")
    else:
        print("not a match")