How can I remove part of an element in a list using the element of another list

So I have list_A and list_B and I need to remove whats in list_B from list_A Example:

list_A = ['I hate the world', 'I love my mother']
list_B = ['I hate', 'love my']

output: list_output = ['the world', 'I mother']

I tried to do

list_A = ['I hate the world', 'I love my mother']

list_B = ['I hate', 'love my']

list_output = [x for x in list_A if x not in list_B] 


print(list_output)

I have also tried a few other things I found on the internet, but they all threw errors or just didn’t do anything, and list comprehensions just seemed the most like what I was trying to achieve.

>Solution :

Here is one way to do it. You have to use nested loops so you can check all combinations until you find a match. Note that what I’m doing leaves the extra spaces in. You can add code to remove those from both halves.

list_A = ['I hate the world', 'I love my mother']
list_B = ['I hate', 'love my']

list_output = []
for phrase in list_A:
    for clause in list_B:
        if clause in phrase:
            i = phrase.find(clause)
            j = phrase[:i] + phrase[i+len(clause):]
            list_output.append(j)
            break
    else: # in case nothing was found
        list_output.append(phrase)

print(list_output)

Output:

[' the world', 'I  mother']