So I am dealing with an object that looks a bit like this:
{
examples: [
{ key: 'value1' },
{ key: 'value1' },
{ key: 'value1' },
{ key: 'value2' },
{ key: 'value2' },
{ key: 'value2' }
]
}
As you can see the values are ordered. I’m trying to get where the value is value2 and I’m sure there is a more efficient way than what I am doing currently, as the actual object is significantly larger and so it takes some time to reach value2.
This is the function I created:
function getValue2 (obj, num) {
if (obj.examples[num] = "value2"){
console.log(obj.examples[num]);
}
else {
getValue2(obj, num + 1);
};
};
var x = JSON.parse(obj);
getValue2(x, 0);
Thank you in advance! 🙂
>Solution :
You can use Array#find:
returns the value of the first element in the provided array that satisfies the provided testing function. If no values satisfy the testing function, undefined is returned.
const data = {
examples: [ { key: 'value1' }, { key: 'value1' }, { key: 'value1' }, { key: 'value2' }, { key: 'value2' }, { key: 'value2' } ]
};
const res = data.examples.find(({ key }) => key === 'value2');
console.log(res);
To get the index of the first occurrence, you can use Array#findIndex:
returns the index of the first element in the array that satisfies the provided testing function. Otherwise, it returns -1, indicating that no element passed the test.
const data = {
examples: [ { key: 'value1' }, { key: 'value1' }, { key: 'value1' }, { key: 'value2' }, { key: 'value2' }, { key: 'value2' } ]
};
const index = data.examples.findIndex(({ key }) => key === 'value2');
console.log(index);