How can I split a long text into array based on empty lines?

April 6, 2022

I have a text file with following content:

...
LogLevelMax=-1
Id=keyboard-setup.service

LogLevelMax=-1
Id= networkd-dispatcher.service

LogLevelMax=-1
Id=systemd-remote-fs.service

LogLevelMax=-1
Id=systemd-journal-flush.service

LogLevelMax=-1
Id=some-other.service
...

I want to save them into an associative array, being key ‘Id’, value ‘LogLevelMax’.
Between each "entity" there are exactly 2 new lines. Between LogLevelMax and Id there is exactly one new line.

First, I try to replace 2 empty lines with a character ‘#’:
cat file.txt | tr "\n\n" "#". But it replaces all new lines with ‘#’, not only exactly 2 new lines.

How can I do it in bash with sed, awk, regex or bash functions?
Thanks.

>Solution :

With bash:

declare -A array
while IFS='=' read -r a b; do
  if [[ "$a" == "Id" ]]; then
    array+=(["$b"]="$c")
  fi
  c="$b"
done < file

And then:

$ for k in "${!array[@]}"; do printf '%s : %s\n' "$k" "${array[$k]}"; done
systemd-journal-flush.service : -1
keyboard-setup.service : -1
systemd-remote-fs.service : -1
networkd-dispatcher.service : -1
some-other.service : -1